If 28C2r : 24C2r – 4 : 225 : 11, find r.


Given:



We know that


And also n! = n(n – 1)(n – 2)…………2.1






(2r)(2r – 1)(2r – 2)(2r – 3) = 11 × 12 × 13 × 14


Equating the corresponding terms on both sides we get,


2r = 14



r = 7


The value of r is 7.


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