If 2nC3 : nC2 = 44 : 3, find n.
Given:
⇒
We know that
And also n! = n(n – 1)(n – 2)…………2.1
⇒ 2 × (2n – 1) × 2 = 44
⇒ 2n – 1 = 11
⇒ 2n = 12
⇒ n = 6
∴ The value of n is 6.