If 2nC3 : nC2 = 44 : 3, find n.


Given:



We know that


And also n! = n(n – 1)(n – 2)…………2.1




2 × (2n – 1) × 2 = 44


2n – 1 = 11


2n = 12



n = 6


The value of n is 6.


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