If (n + 1)! = 90 [(n – 1)!], find n.
Given: (n + 1)! = 90 [(n – 1)!]
To Find : n ?
⇒ (n + 1) × (n) × (n-1)! = 60 [(n – 1)!]
⇒ (n + 1) × (n) = 90
⇒ (n + 1) × (n) = 10 × 9
n = 9
Hence, n = 9