In how many ways can five children stand in a queue?

Given: There are five children

To find: The number of ways in which these children can stand in a queue

Formula used:

Number of arrangements of n things taken all at a time = P(n, n)

∴The total number of ways in which five children can stand in a queue

= the number of arrangements of 5 things taken all at a time

= P(5, 5)

{∵ 0! = 1}

= 5!

= 5 × 4 × 3 × 2 × 1

= 120

Hence, Number of ways in which five children can stand in a queue are 120