Given: the equation of the circle is
⇒ x2 + y2 + 2xcosθ + 2ysinθ - 8 = 0 ..... (1)
We know that for a circle
x2 + y2 + 2ax + 2by + c = 0 .... (2)
⇒ Centre = (- a, - b)
⇒ Radius =
Comparing (1) with (2) we get,
⇒ Centre =
⇒ Centre = (- cosθ, - sinθ)
⇒ Radius =
⇒ Radius =
⇒ Radius =
⇒ Radius = √9
⇒ Radius = 3
∴ The centre and radius of the circle is (- cosθ, - sinθ) and 3.