Let and Find each of the following :

i. 2A – 3B

ii. B – 4C

iii. 3A – C

iv. 3A – 2B + 3C

(i) 2A==

= 3B==

= 2A-3B=-=

=

Hence, 2A-3B=

(ii) 4C==

B-4C=-

==

Hence, B-4C=

(iii) 3A=

= 3A-C=-

= =

Hence, 3A-C=

(iv) 3A==

= 2A==

= 3C==

= 3A-2B+3C=-+

= =

Hence, 3A-2B+3C=