Find the sum of all integers between 100 and 550, which are divisible by 9


given an AP is required of all integers between 100 and 550, which are multiples of 9

To find: the sum of all integers between 100 and 550, which are divisible by 9


So, the sequence is 108, 117, 126….549


It is an AP whose first term is 108 and d is 9


Hence the sum is given by the formula


Now for the finding number of terms, the formula is




n = 50


substituting n in the sum formula we get



s = 16425


11
1