Find the sum of the following series :
0.6 + 0.66 + 0.666 + …. to n terms.
Let
S = 0.6 + 0.66 + 0.666 + .....n terms
Taking 6 as common we get
S = 6(0.1 + 0.11 + 0.111 + ...nterms)
Multiply and divide by 9
⇒
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⇒
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⇒ ![]()
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Now 1 + 1 + 1 + ..n = n
For 0.1 + 0.01 + 0.001 + ..nterms
∴ Common Ratio = r = ![]()
∴ Sum of GP for n terms =
…(1)
⇒ a = 0.1, r =
, n = n
∴ Substituting the above values in (1) we get
⇒ 
⇒ ![]()
For second term the summation is n.
∴ ![]()
⇒ ![]()