Find the equation of the perpendicular to the line segment joining (4, 3) and (– 1 1) if it cuts off an intercept – 3 from y – axis.

Given, A line segment joining (4, 3) and (– 1, 1) if it cuts off an intercept – 3 from y–axis.

To Find: The equation of that line.

Formula used: The equation of line is y = mx + C

Explanation: Here, The required equation of line is y = mx + c

Now, c = – 3 (Given)

Let m be slope of given line = – 1

Slope of line joining (x₁ – x₂) and (y₁ – y₂₎ ,

So, Slope of line joining (4, 3) and (– 1, 1₎ ,

Therefore,

Now, The equation of the line is y = mx + c

2y + 5x + 6 = 0

Hence, The equation of line is 2y + 5x + 6 = 0.