A(6, 3), B(-3, 5), C(4, -2) and (x, 3x) are four points. If ΔDBC : ΔABC = 1 : 2, then x is equal to
The area of a triangle with vertices D (x, 3x), B (− 3, 5) and C (4, − 2) is given below:
Area of ∆DBC
⇒ Area of ∆DBC = 14x – 7 sq units
Similarly, the area of a triangle with vertices A (6, 3), B (− 3, 5) and C (4, − 2) is given below:
Given:
∆DBC: ∆ABC = 1: 2
⇒ 8x – 4 = 7