Evaluate the following limits:


We need to find the limit for:


As limit can be find out simply by putting x = a because it is not taking indeterminate form(0/0) form, so we will be putting x = a


Let, Z =


⇒ Z =


This can be further simplified using a3 – 1 = (a–1)(a2 + a + 1)


⇒ Z =


⇒ Z = (1+a)4 + (1+a)2 + 1


3
1