If and x lies in the IIIrd quadrant, find the values of
and sin 2x.
Given:
We know,
cos 2x = 2 cos2 x – 1
Since,
So,
We know,
cos 2x = 1 – 2 sin2 x
Since,
So,
We know,
sin2 x + cos2 x = 1
⇒ sin2 x = 1 – cos2 x
Since,
So,
Now,
sin 2x = 2(sin x)(cos x)