One of the two events must occur. If the chance of one is 2/3 of the other, then odds in favour of the other are
Let E and F be the two events such that one must occur.
Given,
P(E) = 2/3 P(F)
Also, P(E ∪ F) = 1
P(E) + P(F) = 1
⇒ P(F){2/3 + 1} = 1
∴ P(F) = 3/5
And P(F’) = 1 – 3/5 = 2/5
We have to find
∴ Odds in favour of F = 3/2
As our answer matches only with option (d)
∴ Option (d) is the only correct choice.