If A, B, C are three mutually exclusive and exhaustive events of an experiment such that 3P(A) = 2P(B) = P(C), then P(A) is equal to
Given,
3P(A) = 2P(B) = P(C) = k(say)
∴ P(A) = k/3
P(B) = k/2
And P(C) = k
As events A,B and C are mutually exclusive and exhaustive,
∴ P(A ∪ B ∪ C) = P(A) + P(B) + P(C) = 1
⇒ 1 = k/3 + k/2 + k
⇒ 1 =
⇒ k = 6/11
As, P(A) = k/3 =
Our answer matches with option (b)
∴ Option (b) is the only correct choice