If A, B, C are three mutually exclusive and exhaustive events of an experiment such that 3P(A) = 2P(B) = P(C), then P(A) is equal to


Given,


3P(A) = 2P(B) = P(C) = k(say)


P(A) = k/3


P(B) = k/2


And P(C) = k


As events A,B and C are mutually exclusive and exhaustive,


P(A B C) = P(A) + P(B) + P(C) = 1


1 = k/3 + k/2 + k


1 =


k = 6/11


As, P(A) = k/3 =


Our answer matches with option (b)


Option (b) is the only correct choice

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