Using integration, find the area of the triangle formed by the positive x-axis and tangent and normal to the circle x2 + y2 = 4 at (1, √3).
Given; Circle x2 + y2 = 4 at (1, √3)
Differentiating w.r.t x
∴ The equation of Tangent is;
∴ The equation of Normal is;
Area of the region bounded by the curve y=f(x), the x-axis and the ordinates x=a and x=b, where f(x) is a continuous function defined on [a,b], is given by .
Required Area
= 2√3 sq.units