If O is the origin and the coordinates of A are (a, b, c). Find the direction cosines of OA and the equation of the plane through A at right angles to OA.
As it is given that the required plane is passing through A(a, b, c) and is perpendicular to OA. Let the position vector of this point A be
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And it is also given the plane is normal to the line joining the points O(0,0,0) and A(a, b, c)
Then ![]()
Position vector of
- position vector of ![]()
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Therefore the direction ratios of OA are proportional to a, b, c
Hence the direction cosines are
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We know that the vector equation of a plane passing through the point
and perpendicular/normal to the vector
is given by
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Substituting the values from eqn(i) and eqn(ii) in the above equation, we get
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(by multiplying the two vectors using the formula
)
is the vector equation of a required plane.
Let ![]()
Then, the above vector equation of the plane becomes,
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Now multiplying the two vectors using the formula
, we get
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This is the Cartesian form of equation of the required plane.