Let f, g :R R be defined by f(x) = 2x + 1 and g (x) = x2 – 2, i x R, respectively. Then, find g o f.


We have,


gof(x) = g(f(x))


gof(x) = g(2x+1)


= (2x+1)2 – 2


= (4x2+1+4x) – 2


= 4x2+4x-1


gof = 4x2+4x-1


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