Let A = [–1, 1]. Then, discuss whether the following functions defined on A are one-one, onto or bijective:
k(x) = x2
(iv) Given that, A = [–1, 1]
let k(x1) = k(x2)
⇒ x12= x22
⇒ x1= ± x2
⇒ x1= x2 and x1= - x2
For e.g., k(-1) = |-1| = 1 and k(1) = |1| = 1
⇒ k is not one-one.
We observe that -1 does not have any pre-image in the domain since k(x) = x2 assumes only non-negative values.
i.e. we cannot find any number in domain which will give -1 in co-domain.
⇒ k is not onto
⇒ Hence, k is neither one one nor onto.