Let f : [2, ∞) R be the function defined by f (x) = x2–4x+5, then the range of f is


Given that, f (x) = x2–4x+5


Let f(x) = y


y = x2–4x+5


y = x2–4x+4+1


y = (x-2)2+1


y-1 = (x-2)2


(x-2)2= y-1




Now, if f is real valued function then


y-1 ≥ 0


y ≥ 1


the range of f is [1, ∞).

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