If possible, using elementary row transformations, find the inverse of the following matrices



Let A =


To apply elementary row transformations we write:


A = IA where I is the identity matrix


We proceed with operations in such a way that LHS becomes I and the transformations in I give us a new matrix such that


I = XA


And this X is called inverse of A = A-1


Note: Never apply row and column transformations simultaneously over a matrix.


So we have:



Applying R2 R2 – (5/2)R1



Applying R3 R3 - R2



Applying R1 R1 + R2


=


Applying R2 R2 - 5R3


=


Applying R1 R1 + 2R3


=


Applying R1 (1/2)R1 and R3 2R3


=


As we got Identity matrix in LHS.


A-1 =


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