If A and B are matrices of same order, then (AB’ – BA’) is a
Let C = (AB’ – BA’)
C’ = (AB’ – BA’)’
⇒ C’ = (AB’)’ – (BA’)’
⇒ C’ = (B’)’A’ – (A’)’B’
⇒ C’ = BA’ – AB’
⇒ C’ = -C
∴ C is a skew-symmetric matrix.
Clearly Option (A) matches with our deduction.
∴ Option (A) is the correct.