If A is a square matrix such that A2 = I, then (A – I)3 + (A + I)3 – 7A is equal to
As, (A – I)3 + (A + I)3
Use a3 + b3 = (a + b)(a2 + ab + b2)
Also A2 = I
∴ then (A – I)3 + (A + I)3 – 7A = 2A + 6A – 7A = A
Clearly our answer matches with option (A)
∴ option (A) is the correct answer.