Find a point on the curve y = (x – 3) 2 ,where the tangent is parallel to the chord joining the points (3, 0) and (4, 1).

Question

Philoid · Accepted Answer

Given: Equation of curve, y = (x – 3)²

Firstly, we differentiate the above equation with respect to x, we get

[using chain rule]

Given tangent to the curve is parallel to the chord joining the points (3,0) and (4,1)

i.e.

⇒ 2x – 6 = 1

⇒ 2x = 7

Put in y = (x – 3)² , we have

Hence, the tangent to the curve is parallel to chord joining the points (3,0) and (4,1) at

Find a point on the curve y = (x – 3)2,where the tangent is parallel to the chord joining the points (3, 0) and (4, 1).