Two biased dice are thrown together. For the first die P (6) = 1/2. the other scores being equally likely while for the second die, P (1) = 2/5 and the other scores are equally likely. Find the probability distribution of ‘the number of ones seen’.


Given-


For first die, and



[ P(1)=P(2)=P(3)=P(4)=P(5)]






For second die



Let X= number of one’s seen


For X=0,








=0.04


Hence, the required probability distribution is as below



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