Two biased dice are thrown together. For the first die P (6) = 1/2. the other scores being equally likely while for the second die, P (1) = 2/5 and the other scores are equally likely. Find the probability distribution of ‘the number of ones seen’.
Given-
For first die, and
[∵ P(1)=P(2)=P(3)=P(4)=P(5)]
For second die
Let X= number of one’s seen
For X=0,
=0.04
Hence, the required probability distribution is as below