Two probability distributions of the discrete random variable X and Y are given below.
Prove that E(Y)2=2E(X).
Since, we have to prove that, E(Y2) =2E(X) -----(i)
Taking LHS of equation (i), we have:
E(Y)2= Y2P(Y)
=
……(ii)
Now taking RHS of equation (i) we get:
E(X)= XP(X)
……..(iii)
Thus, from equations (ii) and (iii), we get:
E(Y2) =2E(X)
Hence proved.