If P(A) = 3|10, P(B) = 2|5 and P(A ∪ B) = 3|5, then P(B|A) + P(A|B) equals
We have,
P(A ∪ B) = P(A) + P(B) – P(A ∩ B)
[Additive Law of Probability]
Now, We know that the Property of Conditional Probability:
P(A|B) × P(B) = P(A ∩ B)
…(i)
P(B|A) × P(A) = P(B ∩ A)
…(ii)
Multiplying eq. (i) and (ii), we get
Hence, the Correct option is D