Let A and B be two events such that P(A) = 3/8, P(B) = 5/8 and P(A ∪ B) = 3/4. Then P(A | B).P(A′ | B) is equal to
Given, P(A) = 3/8, P(B) = 5/8 and P(A ∪ B) = 3/4
Now, We know that, P(A ∪ B)=P(A)+P(B)- P(A ∩ B)
P(A ∩ B)=![]()
P(A ∩ B)=![]()
So, P(A|B) =
, then
P(A|B) = ![]()
P(A|B)=2/5
Now, For, P(A’|B)

![]()
P(A’|B)= ![]()
P(A’|B)= ![]()
P(A’|B)= 3/5
Therefore, P(A | B).P(A′|B)= ![]()
Hence, P(A | B).P(A′|B)=6/25