Refer to Question 74 above. The probability that exactly two of the three balls were red, the first ball being red, is

A bag contains 5 red and 3 blue balls

Total Balls in a Bag = 8

For exactly 1 red ball probability should be

Now, 3 Balls are drawn randomly then possibility for getting 1 red ball

P(E)=P(R).P(B)+P(B).P(R)

P(E) =

Hence, P(E) = 4/7