State True or False for the statements in the Exercise.
If A and B are independent, then
P (exactly one of A, B occurs) = P(A)P(B′)+P(B) P(A′)
TRUE
If A and B are independent events. It implies-
P(A ∩ B) = P(A)P(B)
P(A’ ∩ B) = P(A’)P(B)
And P(A ∩ B’) = P(A)P(B’)
P(exactly one of A, B occurs) = P(A’ ∩ B) + P(A ∩ B’)
⇒ P(exactly one of A, B occurs) = P(A’)P(B)+ P(A)P(B’)
∴ Statement is true.