Find out the wavelength of the electron orbiting in the ground state of hydrogen atom.
For electron revolving in nth orbit and having radius of orbit as rn we
have, ![]()
Where,
n = number of the orbit
λ = wavelength
rn = radius of the orbit
For electron orbiting in ground state,
λ=2π×0.53 Å [ ∵ n = 1 ; rn = 0.53 Angstroms]
∴ λ = 2π × 0.53 ![]()
= 3.331 Å