How fast should a man of 50 kg run so that his kinetic energy will be 625 J?

Given that ,
m(mass)= 50 kg and K.E.(kinetic energy) = 625 j

As we know that:-

K.E.=1/2×(m×v²) 

1/2×(50×v²) = 625

v² =(625  × 2)/50=1250/50=25

v = √25= 5 m/s            Ans