Find the values of a and b so that the function
f(x) =
is differentiable at each x € R.
For differentiability at x = 1,
LHD(at x = 1) = RHD(at x = 1)
(LHD at x = 1) =
=
=
=
= - 5
(RHD at x = 1) =
=
=
=
= b
Since, f(x) is differentiable , So
(LHD at x = 1) = (RHD at x = 1)
-5 = b
F(1) = 1 + 3 + a
= 4 + a
LHL =
=
=
=
RHL =
=
=
= b + 2