Show that the three points A(2, 3, 4), B(-1, 2, -3) and C(-4, 1, -10) are collinear and find the ratio in which C divides AB.
Given: A(2, 3, 4), B(-1, 2, -3) and C(-4, 1, -10)
To prove: A, B and C are collinear
To find: the ratio in which C divides AB
Formula used:
Section Formula:
A line AB is divided by C in m:n where A(x, y, z) and B(a, b, c).
The coordinates of C is given by,
Let C divides AB in ratio k: 1
Three points are collinear if the value of k is the same for x, y and z coordinates
Therefore, m = k and n = 1
A(2, 3, 4), B(-1, 2, -3) and C(-4, 1, -10)
Coordinates of C using section formula:
On comparing:
⇒ -k + 2 = -4(k + 1)
⇒ -k + 2 = -4k – 4
⇒ 4k – k = - 2 – 4
⇒ 3k = -6
⇒ k = -2
⇒ 2k + 3 = k + 1
⇒ 2k – k = 1 – 3
⇒ k = – 2
⇒ -3k + 4 = -10(k + 1)
⇒ -3k + 4 = -10k – 10
⇒ -3k + 10k = -10 – 4
⇒ 7k = -14
⇒ k = -2
The value of k is the same in all three times
Hence, A, B and C are collinear
As k = -2
C divides AB externally in ratio 2:1