Write the coordinates of the foci of the hyperbola 9x2 – 16y2 = 144.
Given: 9x2 – 16y2 = 144
To find: coordinates of the foci f(m,n)
9x2 – 16y2 = 144
Formula used:
For hyperbola
Eccentricity(e) is given by,
Foci is given by (±ae, 0)
Here, a = 4 and b = 3
⇒ c = 5
Therefore,
Foci: (±5, 0)