If e1 and e2 are respectively the eccentricities of the ellipse
and the hyperbola
, then the relation between e1 and e2 is
Given: e1 and e2 are respectively the eccentricities of the ellipse
and the hyperbola ![]()
To find: value of 2e12 + e22
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Eccentricity(e) of hyperbola is given by,
![]()
Here a = 3 and b = 2
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Therefore,
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For ellipse:
![]()

Eccentricity(e) of ellipse is given by,
![]()
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Therefore,



Substituting values from (1) and (2) in 2e12 + e22
2e12 + e22

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= 3
Hence, value of 2e12 + e22 is 3