The eccentricity of the hyperbola x2 – 4y2 = 1 is
Given: x2 – 4y2 = 1
To find: eccentricity(e)
x2 – 4y2 = 1
Formula used:
For hyperbola
Eccentricity(e) is given by,
Here, a = 1 and
Therefore,
Hence, eccentricity is