the foci of the hyperbola 9x² – 16y² = 144 are

Given: 9x² – 16y² = 144

To find: coordinates of the foci f(m,n)

9x² – 16y² = 144

Formula used:

For hyperbola

Eccentricity(e) is given by,

Foci is given by (±ae, 0)

Here, a = 4 and b = 3

⇒ c = 5

Therefore,

Foci: (±5, 0)