Find the least positive integral value of n for which
is real.
Let us assume the given complex number be ![]()
Multiplying and dividing with 1+i
⇒ ![]()
⇒ ![]()
We know that i2=-1
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
We know that i2k is real for k>0.
So, the smallest positive integral ‘n’ that can make
real is 2.
∴ The smallest positive integral value of ‘n’ is 2.