Express the following complex numbers in the form ![]()
1 – sin α + i cos α
Given Complex number is z=1-sin
+icos![]()
We know that sin2θ+cos2θ=1, sin2θ=2sinθcosθ, cos2θ=cos2θ-sin2θ.
⇒ ![]()
⇒ ![]()
e know that the polar form of a complex number Z=x+iy is given by Z=|Z|(cosθ+isinθ)
Where,
|Z|=modulus of complex number=![]()
θ =arg(z)=argument of complex number=![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ ![]()
We know that sine and cosine functions are periodic with period 2![]()
Here We have 3 intervals as follows:
(i) ![]()
(ii) ![]()
(iii) ![]()
Case(i):
In the interval
,
and also ![]()
so,
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒
.(∵ θ lies in 1st quadrant)
∴ The polar form is
.
Case(ii):
In the interval
,
and also ![]()
so,
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒
. (∵ θ lies in 4th quadrant)
⇒ ![]()
∴ The polar form is
.
Case(iii):
In the interval
,
and also ![]()
so,
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒
.(since θ presents in first quadrant and tan’s period is
)
⇒
.
∴ The polar form is
.