Q2 of 23 Page 2

If (x + 1, 1) = (3y, y - 1), find the values of x and y.

given: (x + 1, 1) = (3y, y - 1)


To find: values of a and b


By the definition of equality of ordered pairs, we have


x + 1 = 3y and  1 = y - 1


⇒ x = 3y - 1 and  y = 2

So,

x = 3(2) - 1
  = 6 - 1
  = 5


⇒ x = 5 and y = 2

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