Q18 of 30 Page 10

Find the equation of the line parallel to y-axis and drawn through the point of intersection of the lines x – 7y + 5 = 0 and 3x + y = 0.

The equation of any line parallel to the y – axis is of the form


x = a -------- (1)


The two given lines are


x – 7y + 5 = 0 ---------(2)


3x + y = 0 ------- (3)


Multiply eq (2) with 3 and subtract eq(3) from it to get,

3x - 21y + 15 - 3x - y = 0

-22y = -15



Put value of y in eq(3) to get,






Thus,


is the point of intersection of lines (2) and (3).


Since, line x = a pass through point a =


Therefore, the required equation of the line is x =

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