In a rectangle ABCD, prove that ΔACB ≅ΔCAD.

In ΔACB and ΔCAD
AB = CD [Opposite sides of a rectangle are equal]
BC = DA
AC = CA Common
ΔACB ≅ΔCAD (SSS Congurency)
AI is thinking…
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.