Q7 of 50 Page 6

Write a Pythagorean triplet whose one number is 18.

For any natural number m > 1, 2m, m2 - 1, m2+ 1 forms a Pythagorean triplet
Pythagorean triplet : A Pythagorean triple consists of three positive integers a, b, and c, such that a2 + b2 = c2.


Let us take 2m = 18


Therefore, m = 9


m2 – 1 = (9)2 – 1 = 81 – 1 = 80


m2 + 1 = (9)2 + 1 = 81 + 1 = 82


Hence, the triplet is 18, 80 and 82.


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