The diagonals of a quadrilateral bisect each other.
Prove that this quadrilateral as a parallelogram.

Given here a quadrilateral of sides MN , NK, KL and ML
Also it is given that the diagonals of the quadrilateral bisect each other.
To prove: Quad KLMN is a parallelogram
Proof: As the diagonals bisect each other,
So, NO=OL and KO=OM……………..(1)
Now, in ∆KOL and ∆NOM,
∠KOL=∠NOM (vertically opposite angles)
KO=OM (from (1))
NO=OL (from (1))
∴ ∆KOL
∆NOM (by SAS rule)
So, KL=NM (by cpct)
∠OMN=∠OKL (by cpct)………..(2)
∠OLK=∠ONM (by cpct)…………(3)
Similarly, ∆KON
∆LOM (by SAS rule)
So, KN=LM (by cpct)
∠ONK=∠OLM (by cpct)………..(4)
∠OKN=∠OML (by cpct)…………(5)
From (2) and (3) ,
We can say they are alternate interior angles.
So, KL||NM
Similarly, From (4) and (5) ,
We can say they are alternate interior angles.
So, KN||ML
Hence, KLMN is a parallelogram.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.