Q4 of 11 Page 96

∆ AMT ~ ∆ AHE. In ∆ AMT, AM = 6.3 cm, ∠TAM = 50°, AT = 5.6 cm.Construct ∆ AHE.

Steps of construction:


i. Draw a triangle AMT, with AM = 6.3 cm, ∠TAM = 50° cm and AT = 5.6 cm, choosing AM as base.



ii. Below AM, draw an acute angle ∠MAX.



iii. Mark four points A1, A2, A3, A4, A5, A6 and A7 on AX, such that AA1 = A1A2 =…= A6A7 [As ratio is 7:5, we choose 7 points]



iv. Join MA7 and Draw HA5 || MA7



v. Draw HE || MT



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