Let f : R → R : f(x) = x2 + 1. Find f–1 {10}.
Given:
f : R → R : f(x) = x2 + 1
To find inverse of f(x)
Let y = f(x)
y = x2 + 1
y-1 = ![]()
x = ![]()
f–1 (x) = ![]()
Substituting x = 10,
f–1 (10) =
=
= 3
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