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9. Combinations
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Q6 of 68 Page 330

If 2nC3: nC3 = 12 : 1, find n.

Given: 2nC3: nC3 = 12 : 1


To find: n=?


2nC3: nC3 = 12 : 1


⇒


⇒


⇒


⇒


⇒


⇒


⇒


⇒2n-1=3(n-2)


⇒2n-1=3n-6


⇒n=6-1=5


Ans:n=5


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Questions · 68
9. Combinations
1 1 1 1 1 1 2 3 4 5 6 7 8 9 10 11 12 13 14 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 1 2 3 4 5 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
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