If
, prove that
,
.
Given, ![]()
To prove: ![]()
![]()
Note:
I. Sum of first n natural numbers, 1 + 2 +3+…n,

II. Sum of squares of first n natural numbers, 12 + 22 + 32+….n2,

III. Sum of cubes of first n natural numbers, 13 + 23 + 33 +…..n3,

IV. Sum of a constant k, N times,

So,
![]()
Now, the Left hand side of the condition given in the question can be written as,

The required LHS, ![]()






![]()
So,

,
With
,
Hence proved.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
