Q16 of 30 Page 516

The angles of a quadrilateral are in AP, and the greatest angle is double the least. Express the least angle in radians.

Let the smallest term be x, and the largest term be 2x


Then AP formed= x, ?, ?, 2x


so,




360°= 4/2 [x+ 2x]....[We know that → a+(n-1) d= last term= 2x]


⇒ 180°= 3x


⇒ x= 60°


Now, 60° is least angle.


= 60°= π/180° × 60°


⇒ 60° = π/3 rad


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