A rod of length 15 cm moves with its ends always touching the coordinate axes. Find the equation of the locus of a point P on the rod, which is at a distance of 3 cm from the end in contact with the x-axis.
Given: A rod of length 15 cm moves with its ends always touching the coordinate axes. A point P on the rod, which is at a distance of 3 cm from the end in contact with the x-axis
Need to find: Find the equation of the locus of a point P

Here AB is the rod making an angle
with the x-axis.
Here AP = 3.
PB = AB – AP = 12 – 3 = 9 cm
Here, PQ is the perpendicular drawn from the x-axis and RP is the perpendicular drawn from y-axis.
Let, the coordinates of the point P is (x, y).
Now, in the triangle
BPQ,
cos
= ![]()
And in the triangle
PAR,
sin
= ![]()
We know, sin2
+ cos2
= 1
⇒ ![]()
This is the locus of the point P.
Couldn't generate an explanation.
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